Monday, January 29, 2007

1G TABLE:Decelerate for 1 Year

CONTENT
INTRODUCTION
1G DECEL DAYS 0-15LEGEND
1G DECEL DAYS 16-30          INTRODUCTION
1G DECEL DAYS 31-45IV: time (t)
1G DECEL DAYS 46-60AU and c
1G DECEL DAYS 61-75GRAVITY
1G DECEL DAYS 76-90DAILY DIFF
1G DECEL DAYS 91-105SPOT VEL (AU/dy)
1G DECEL DAYS 106-120SPOT VEL (%c/dy)
1G DECEL DAYS 121-135 COUNTDOWN
1G DECEL DAYS 136-150 BRAINSTORM
1G DECEL DAYS 151-165 DIST TO GO (AU)
1G DECEL DAYS 166-180 DIST as LY
1G DECEL DAYS 181-195 FUEL FACTS O/V
1G DECEL DAYS 196-210CLASSICAL MOM
1G DECEL DAYS 211-225RELATIVITY
1G DECEL DAYS 226-240EFFICIENCY
1G DECEL DAYS 241-255DAILY FUEL
1G DECEL DAYS 256-270 HOW FAST?
1G DECEL DAYS 271-285 HOW FAR?
1G DECEL DAYS 286-300HOW FUEl?
1G DECEL DAYS 301-315 INITIAL GW
1G DECEL DAYS 316-330DAILY GW
1G DECEL DAYS 331-345CLASSICAL FUEL
1G DECEL DAYS 346-360 PRACTICAL FUEL
1G DECEL DAYS 361-365¼CONCLUDE
SUMMARY
1G Deceleration for 365¼ Days
time
(t)
Spot Velocity
(Vt)
Countdown Distance
(dt)
Total Fuel
(ft)
1G Acc7G Acc7G Dec1G Dec
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LEGEND
time (t) is Independent Variable (IV)
which counts deceleration days up from 0 to 365¼.
Spot Velocity (Vt); same formula as acceleration.
However, decelerated velocities require
"reverse order"; thus, use "
365¼-t" as exponent. 
Spot Velocity (VAU) Convert Astro Units per day to %c.
 
 EXAMPLE:  Value = 110.72 AU/dy × c/173.AU/dy = 63.95% c.
 IDENTITY:  c = 173.145 AU/day. 
Countdown Distance (dt) 
Uses same "Einsteinian" formula as for acceleration.

Deceleration leads to shrinking distances; countdown to 0 AUs.
Countdown Distance (dLY) IDENTITY: 1 LY = 63,240 AUs
Convert Astro Units (AUs) to Light Years (LYs)
22,945.2 AU × 1 LY/63,240 AU = 0.3628 LY
Total Fuel (ft) is total fuel consumed due to
 G-force propulsion: Assume:
ε∇ = 0.0468% GW/day
After 1 yr of 1G acceleration, total fuel is 15.72% GW0.
Deceleration's G-force daily fuel increases from 15.72% GW0.









0 days111.80 AU/dy64.57% c23,875.9 AU0.3775 LY15.72% GW0
1 days111.38 AU/dy 64.33% c23,710.3 AU0.3749 LY15.76% GW0
2 days111.25 AU/dy  64.23% c23,599.0 AU0.3732 LY15.79% GW0
3 days111.08 AU/dy 64.13% c23,487.9 AU0.3714 LY15.83% GW0
4 days110.90 AU/dy64.05% c23,376.9 AU0.3697 LY15.87% GW0
5 days110.72 AU/dy63.95% c23,266.1 AU0.3679 LY15.91% GW0
6 days110.55 AU/dy63.85% c23,277.0 AU0.3662 LY15.95% GW0
7 days110.37 AU/dy63.74% c23,166.2 AU0.3644 LY15.99% GW0
8 days 110.19 AU/dy63.64% c23,055.6 AU0.3636 LY16.03% GW0
9 days 110.01 AU/dy 63.54% c22,945.2 AU0.3628 LY16.07% GW0
10 days109.83 AU/dy63.43% c 22,835.0 AU0.3611 LY16.11% GW0
11 days109.65 AU/dy63.33% c22,725.0 AU0.3593 LY16.15% GW0
12 days109.47 AU/dy63.23% c22,615.1 AU0.3576 LY16.19% GW0
13 days 109.29AU/dy63.12% c22,505.4 AU 0.3559 LY16.23% GW0
14 days109.11 AU/dy 63.02% c22,395.9 AU0.3541 LY16.27% GW0
15 days108.93 AU/dy62.91% c22,286.6 AU0.3524 LY16.31% GW0
Given
Vt=(1- (1-Δ)365¼-tc
dt=c×(365¼-t) +Vt

ln(1-Δ)
1-(1-ε∇)t+365¼
1G Acc7G Acc7G Dec1G Dec
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INTRODUCTION

RECALL THREE PHASES:
Ph. I: Accelerate for one year at G-force propulsion.  Achieve considerable velocity and simulate gravity.
Ph. II: Cruise for several years to nearby star, at considerable speed, perhaps 64% light speed (c). Simulate Earth like gravity via centrifugal force due to longitudinal spin.
Ph. III: Decelerate for one year at G-force in reverse of Phase I.  Achieve operational velocity upon arrival at destination stellar system. 
This table assumes success for PHASEs I & II, and now considers PHASE III.
16 days108.75 AU/dy62.81% c22,177.4 AU0.3507 LY16.34% GW0
17 days108.57 AU/dy62.70% c22,068.5 AU0.3490 LY16.38% GW0
18 days108.38 AU/dy62.60% c21,959.7 AU0.3472 LY16.42% GW0
19 days108.20 AU/dy62.49% c21,851.1 AU0.3455 LY16.46% GW0
20 days108.02 AU/dy62.38% c21,742.7 AU0.3438 LY16.50% GW0
21 days107.83 AU/dy62.28% c21,634.4 AU0.3421 LY16.54% GW0
22 days107.65 AU/dy62.17% c21,526.4 AU0.3404 LY16.58% GW0
23 days107.46 AU/dy62.06% c21,418.5 AU0.3387 LY16.62% GW0
24 days107.27 AU/dy61.96% c21,310.9 AU0.3370 LY16.66% GW0
25 days107.09 AU/dy61.85% c21,203.4 AU0.3353 LY16.70% GW0
26 days106.90 AU/dy61.74% c21,096.1 AU0.3336 LY16.74% GW0
27 days106.71 AU/dy61.63% c20,989.0 AU0.3319 LY16.77% GW0
28 days106.52 AU/dy61.52% c20,882.1 AU0.3302 LY16.81% GW0
29 days106.33 AU/dy61.41% c20,775.3 AU0.3285 LY16.85% GW0
30 days106.14 AU/dy61.30% c20,668.8 AU0.3268 LY16.89% GW0
time
(t)
Spot Velocity
(Vt)
Countdown Distance
(dt)
Total Fuel
(ft)
1G Acc 7G Acc7G Dec1G Dec
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INDEPENDENT VARIABLE: time (t)
Each row is numbered sequentially
from 0 days  to 365¼ days
to reflect days of deceleration.



31 days105.95 AU/dy61.19% c20,562.4 AU0.3251 LY16.93% GW0
32 days105.76 AU/dy61.08% c20,456.3 AU0.3235 LY16.97% GW0
33 days105.57 AU/dy60.97% c20,350.3 AU0.3218 LY17.01% GW0
34 days105.38 AU/dy60.86% c20,244.5 AU0.3201 LY17.05% GW0
35 days105.19 AU/dy60.75% c20,138.9 AU0.3185 LY17.09% GW0
36 days105.00 AU/dy60.64% c20,033.5 AU0.3168 LY17.12% GW0
37 days104.80 AU/dy60.53% c19,928.3 AU0.3151 LY17.16% GW0
38 days104.61 AU/dy60.42% c19,823.3 AU0.3135 LY17.20% GW0
39 days104.41 AU/dy60.30% c19,718.5 AU0.3118 LY17.24% GW0
40 days104.22 AU/dy60.19% c19,613.9 AU0.3101 LY17.28% GW0
41 days104.02 AU/dy60.08% c19,509.4 AU0.3085 LY17.32% GW0
42 days103.83 AU/dy59.97% c19,405.2 AU0.3069 LY17.36% GW0
43 days103.63 AU/dy59.85% c19,301.2 AU0.3052 LY17.40% GW0
44 days103.43 AU/dy59.74% c19,197.3 AU0.3036 LY17.43% GW0
45 days103.24 AU/dy59.62% c19,093.7 AU0.3019 LY17.47% GW0
Given
(1-(1-Δ)365¼-tc

dt=c × (365¼-t) + Vt

ln(1-Δ)
1-(1-ε∇)t+365¼
1G Acc 7G Acc 7G Dec 1G Dec
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ESSENTIAL CONSTANTS: 
ASTRO UNIT:  AU = 149,597,871 km 
LIGHT SPEED:  c = 173.144 AU/day

c =299,792.5 km

sec
=173.1439 AU

day
= c
Different expressions for lightspeed, c.



46 days103.04 AU/dy59.51% c18,990.2 AU0.3003 LY17.51% GW0
47 days102.84 AU/dy59.40% c18,887.0 AU0.2987 LY17.55% GW0
48 days102.64 AU/dy59.28% c18,784.0 AU0.2970 LY17.59% GW0
49 days102.44 AU/dy59.16% c18,681.1 AU0.2954 LY17.63% GW0
50 days102.24 AU/dy59.05% c18,578.5 AU0.2938 LY17.67% GW0
51 days102.04 AU/dy58.93% c18,476.0 AU0.2922 LY17.70% GW0
52 days101.84 AU/dy58.82% c18,373.8 AU0.2905 LY17.74% GW0
53 days101.64 AU/dy58.70% c18,271.7 AU0.2889 LY17.78% GW0
54 days101.43 AU/dy58.58% c18,169.9 AU0.2873 LY17.82% GW0
55 days101.23 AU/dy58.46% c18,068.3 AU0.2857 LY17.86% GW0
56 days101.02 AU/dy58.35% c17,966.8 AU0.2841 LY17.90% GW0
57 days100.82 AU/dy58.23% c17,865.6 AU0.2825 LY17.94% GW0
58 days100.62 AU/dy58.11% c17,764.6 AU0.2809 LY17.97% GW0
59 days100.41 AU/dy57.99% c17,663.8 AU0.2793 LY18.01% GW0
60 days100.20 AU/dy57.87% c17,563.1 AU0.2777 LY18.05% GW0
time
(t)
Spot Velocity
(Vt)
Countdown Distance
(dt)
Total Fuel
(ft)
1G Acc 7G Acc 7G Dec 1G Dec
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EARTH GRAVITY
Different terms for g= 9.8065 m/sec²
g =0.2826%c

day
=847  kps

day
=0.489 AU

day2
After one day of g-force propulsion, 
vessel velocity = .002826c, light speed.



61 days100.00 AU/dy57.75% c17,462.7 AU0.2761 LY18.09% GW0
62 days99.79 AU/dy57.63% c17,362.5 AU0.2745 LY18.13% GW0
63 days99.58 AU/dy57.51% c17,262.6 AU0.2730 LY18.17% GW0
64 days99.37 AU/dy57.39% c17,162.8 AU0.2714 LY18.20% GW0
65 days99.16 AU/dy57.27% c17,063.2 AU0.2698 LY18.24% GW0
66 days98.95 AU/dy57.15% c16,963.8 AU0.2682 LY18.28% GW0
67 days98.74 AU/dy57.03% c16,864.7 AU0.2667 LY18.32% GW0
68 days98.53 AU/dy56.91% c16,765.7 AU0.2651 LY18.36% GW0
69 days98.32 AU/dy56.78% c16,667.0 AU0.2636 LY18.39% GW0
70 days98.11 AU/dy56.66% c16,568.5 AU0.2620 LY18.43% GW0
71 days97.90 AU/dy56.54% c16,470.2 AU0.2604 LY18.47% GW0
72 days97.68 AU/dy56.42% c16,372.1 AU0.2589 LY18.51% GW0
73 days97.47 AU/dy56.29% c16,274.2 AU0.2573 LY18.55% GW0
74 days97¼ AU/dy56.17% c16,176.5 AU0.2558 LY18.59% GW0
75 days97.04 AU/dy56.04% c16,079.1 AU0.2543 LY18.62% GW0
Given
(1-(1-Δ)365¼-tc

dt=c × (365¼-t) + Vt

ln(1-Δ)
1-(1-ε∇)t+365¼
1G Acc 7G Acc 7G Dec 1G Dec
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DAILY DECREMENT (Δ): 
1 day of reverse g-force propulsion
decreases velocity equal to 0.2826%c 
as observed by crew of interstellar vessel.**
day × g

c
=86,400 sec × 9.8065m/sec²

299,792,500 m/sec
=0.2826%
Compliments of Thot Exp Brainstorm!



76 days96.82 AU/dy55.92% c15,981.9 AU0.2527 LY18.66% GW0
77 days96.61 AU/dy55.79% c15,884.8 AU0.2512 LY18.70% GW0
78 days96.39 AU/dy55.67% c15,788.0 AU0.2497 LY18.74% GW0
79 days96.17 AU/dy55.54% c15,691.4 AU0.2481 LY18.78% GW0
80 days95.95 AU/dy55.42% c15,595.1 AU0.2466 LY18.81% GW0
81 days95.73 AU/dy55.29% c15,498.9 AU0.2451 LY18.85% GW0
82 days95.51 AU/dy55.16% c15,403.0 AU0.2436 LY18.89% GW0
83 days95.29 AU/dy55.04% c15,307.3 AU0.2421 LY18.93% GW0
84 days95.07 AU/dy54.91% c15,211.8 AU0.2405 LY18.97% GW0
85 days94.85 AU/dy54.78% c15,116.5 AU0.2390 LY19.00% GW0
86 days94.63 AU/dy54.65% c15,021.5 AU0.2375 LY19.04% GW0
87 days94.41 AU/dy54.52% c14,926.7 AU0.2360 LY19.08% GW0
88 days94.18 AU/dy54.40% c14,832.1 AU0.2345 LY19.12% GW0
89 days93.96 AU/dy54.27% c14,737.7 AU0.2330 LY19.16% GW0
90 days93.74 AU/dy54.14% c14,643.5 AU0.2316 LY19.19% GW0
time
(t)
Spot Velocity
(Vt)
Countdown Distance
(dt)
Total Fuel
(ft)
1G Acc 7G Acc 7G Dec 1G Dec
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SPOT VELOCITY (AU/DAY)
COMPUTE Velocity (VAU) as AU/day.
EXAMPLE: t = 91 days, compute as follows:
Vt=(1 - [1-Δ]365¼-t) ×c
V91=(1 - (0.99717)274¼)×173.145 AU/day
V91 = 93.51 AU/day
91 days93.51 AU/dy54.01% c14,549.6 AU0.2301 LY19.23% GW0
92 days93.28 AU/dy53.88% c14,455.9 AU0.2286 LY19.27% GW0
93 days93.06 AU/dy53.75% c14,362.4 AU0.2271 LY19.31% GW0
94 days92.83 AU/dy53.61% c14,269.2 AU0.2256 LY19.34% GW0
95 days92.60 AU/dy53.48% c14,176.2 AU0.2242 LY19.38% GW0
96 days92.37 AU/dy53.35% c14,083.4 AU0.2227 LY19.42% GW0
97 days92.15 AU/dy53.22% c13,990.8 AU0.2212 LY19.46% GW0
98 days91.92 AU/dy53.09% c13,898.5 AU0.2198 LY19.50% GW0
99 days91.69 AU/dy52.95% c13,806.4 AU0.2183 LY19.53% GW0
100 dy91.45 AU/dy52.82% c13,714.5 AU0.2169 LY19.57% GW0
101 dy91.22 AU/dy52.69% c13,622.8 AU0.2154 LY19.61% GW0
102 dy90.99 AU/dy52.55% c13,531.4 AU0.2140 LY19.65% GW0
103 dy90.76 AU/dy52.42% c13,440.3 AU0.2125 LY19.68% GW0
104 dy90.52 AU/dy52.28% c13,349.3 AU0.2111 LY19.72% GW0
105 dy90.29 AU/dy52.15% c13,258.6 AU0.2097 LY19.76% GW0
Given
(1-(1-Δ)365¼-tc

dt=c × (365¼-t) + Vt

ln(1-Δ)
1-(1-ε∇)t+365¼
1G Acc 7G Acc 7G Dec 1G Dec
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SPOT VELOCITY (V%c)
as per cent light speed, c.
V%c = (1 - (1-Δ)365¼-t) × c
V%c =100 per centiles

1.0
×c



EXAMPLE:V106=[1-(0.997174)259¼]× c = 52.01% c
106 dy90.05 AU/dy52.01% c13,168.1 AU0.2082 LY19.80% GW0
107 dy89.82 AU/dy51.87% c13,077.9 AU0.2068 LY19.83% GW0
108 dy89.58 AU/dy51.74% c12,987.9 AU0.2054 LY19.87% GW0
109 dy89.35 AU/dy51.60% c12,898.1 AU0.2040 LY19.91% GW0
110 dy89.11 AU/dy51.46% c12,808.6 AU0.2025 LY19.95% GW0
111 dy88.87 AU/dy51.33% c12,719.3 AU0.2011 LY19.98% GW0
112 dy88.63 AU/dy51.19% c12,630.2 AU0.1997 LY20.02% GW0
113 dy88.39 AU/dy51.05% c12,541.4 AU0.1983 LY20.06% GW0
114 dy88.15 AU/dy50.91% c12,452.8 AU0.1969 LY20.10% GW0
115 dy87.91 AU/dy50.77% c12,364.5 AU0.1955 LY20.13% GW0
116 dy87.67 AU/dy50.63% c12,276.4 AU0.1941 LY20.17% GW0
117 dy87.43 AU/dy50.49% c12,188.6 AU0.1927 LY20.21% GW0
118 dy87.18 AU/dy50.35% c12,100.9 AU0.1913 LY20.25% GW0
119 dy86.94 AU/dy50.21% c12,013.6 AU0.1900 LY20.28% GW0
120 dy86.69 AU/dy50.07% c11,926.5 AU0.1886 LY20.32% GW0
time
(t)
Spot Velocity
(Vt)
Countdown Distance
(dt)
Total Fuel
(ft)
1G Acc 7G Acc 7G Dec 1G Dec
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SPOT VELOCITY COUNTDOWN
G-force Deceleration Table decrements ship's velocity from cruise velocity of 111.8 AU/day, reverse order of G-force Acceleration Table, which counts velocity up from zero to 111.8 AU/day.
Daily decrements of ship's velocity are Δ = 0.283% c.  

Accordingly, vessel velocity shrinks same daily percentage of light speed, c; eventually reaching a relative zero velocity at the stellar destination to conduct normal ops. 

Without the deceleration phase, the interstellar vessel speeds quickly past the stellar destination, barely able to grab a peek.
121 dy86.45 AU/dy49.93% c11,839.6 AU0.1872 LY20.36% GW0
122 dy86.20 AU/dy49.79% c11,752.9 AU0.1858 LY20.39% GW0
123 dy85.96 AU/dy49.64% c11,666.6 AU0.1845 LY20.43% GW0
124 dy85.71 AU/dy49.50% c11,580.4 AU0.1831 LY20.47% GW0
125 dy85.46 AU/dy49.36% c11,494.5 AU0.1818 LY20.51% GW0
126 dy85.21 AU/dy49.21% c11,408.9 AU0.1804 LY20.54% GW0
127 dy84.96 AU/dy49.07% c11,323.5 AU0.1791 LY20.58% GW0
128 dy84.71 AU/dy48.93% c11,238.4 AU0.1777 LY20.62% GW0
129 dy84.46 AU/dy48.78% c11,153.5 AU0.1764 LY20.65% GW0
130 dy84.21 AU/dy48.64% c11,068.8 AU0.1750 LY20.69% GW0
131 dy83.96 AU/dy48.49% c10,984.4 AU0.1737 LY20.73% GW0
132 dy83.71 AU/dy48.34% c10,900.3 AU0.1724 LY20.77% GW0
133 dy83.45 AU/dy48.20% c10,816.4 AU0.1710 LY20.80% GW0
134 dy83.20 AU/dy48.05% c10,732.8 AU0.1697 LY20.84% GW0
135 dy82.94 AU/dy47.90% c10,649.4 AU0.1684 LY20.88% GW0
Given
(1-(1-Δ)365¼-tc

dt=c × (365¼-t) + Vt

ln(1-Δ)
1-(1-ε∇)t+365¼
1G Acc 7G Acc 7G Dec 1G Dec
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TE BRAINSTORMS DAILY DIFF (Δ) 
DAILY DIFFERENCE: Δ =0.2816% c/day 

Observers at departure (Earth) and  stellar destination
constantly measure vessel's decreasing velocity.
Vessel crew sees Earth retreating slower
and dest star as approaching slower.
 every day of  1G deceleration.
HOWEVER, ALL OBSERVERS (DEPT, VESSEL, DEST)  
continually measure light speed as persistent c.

DAILY REMAINDER: 
R=1-Δ=99.7174% c/day
136 dy82.69 AU/dy47.76% c10,566.3 AU0.1671 LY20.91% GW0
137 dy82.43 AU/dy47.61% c10,483.4 AU0.1658 LY20.95% GW0
138 dy82.17 AU/dy47.46% c10,400.8 AU0.1645 LY20.99% GW0
139 dy81.91 AU/dy47.31% c10,318.5 AU0.1632 LY21.03% GW0
140 dy81.66 AU/dy47.16% c10,236.4 AU0.1619 LY21.06% GW0
141 dy81.40 AU/dy47.01% c10,154.6 AU0.1606 LY21.10% GW0
142 dy81.14 AU/dy46.86% c10,073.0 AU0.1593 LY21.14% GW0
143 dy80.88 AU/dy46.71% c9,991.7 AU0.1580 LY21.17% GW0
144 dy80.61 AU/dy46.56% c9,910.6 AU0.1567 LY21.21% GW0
145 dy80.35 AU/dy46.41% c9,829.8 AU0.1554 LY21.25% GW0
146 dy80.09 AU/dy46¼% c9,749.3 AU0.1542 LY21.28% GW0
147 dy79.82 AU/dy46.10% c9,669.0 AU0.1529 LY21.32% GW0
148 dy79.56 AU/dy45.95% c9,589.1 AU0.1516 LY21.36% GW0
149 dy79.29 AU/dy45.80% c9,509.3 AU0.1504 LY21.39% GW0
150 dy79.03 AU/dy45.64% c9,429.9 AU0.1491 LY21.43% GW0
time
(t)
Spot Velocity
(Vt)
Countdown Distance
(dt)
Total Fuel
(ft)
1G Acc 7G Acc 7G Dec 1G Dec
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COUNTDOWN DISTANCE (dt) as (AUs)
Distance shrinks on the way to destination.
dt = c × (365¼-t) +Vt

ln(1-Δ)
 RECALL: Spot Velocity (Vt)  is in the dt formula.

EX:d151=173.145AU
day
×211¼  days +78.76AU/dy
-.00283
= 9,350.7AU
151 dy78.76 AU/dy45.49% c9,350.7 AU0.1479 LY21.47% GW0
152 dy78.49 AU/dy45.33% c9,271.7 AU0.1466 LY21.50% GW0
153 dy78.22 AU/dy45.18% c9,193.1 AU0.1454 LY21.54% GW0
154 dy77.96 AU/dy45.02% c9,114.7 AU0.1441 LY21.58% GW0
155 dy77.69 AU/dy44.87% c9,036.5 AU0.1429 LY21.61% GW0
156 dy77.41 AU/dy44.71% c8,958.7 AU0.1417 LY21.65% GW0
157 dy77.14 AU/dy44.55% c8,881.1 AU0.1404 LY21.69% GW0
158 dy76.87 AU/dy44.40% c8,803.8 AU0.1392 LY21.72% GW0
159 dy76.60 AU/dy44.24% c8,726.7 AU0.1380 LY21.76% GW0
160 dy76.32 AU/dy44.08% c8,650.0 AU0.1368 LY21.80% GW0
161 dy76.05 AU/dy43.92% c8,573.5 AU0.1356 LY21.83% GW0
162 dy75.77 AU/dy43.76% c8,497.3 AU0.1344 LY21.87% GW0
163 dy75.50 AU/dy43.60% c8,421.3 AU0.1332 LY21.91% GW0
164 dy75.22 AU/dy43.44% c8,345.7 AU0.1320 LY21.94% GW0
165 dy74.94 AU/dy43.28% c8,270.3 AU0.1308 LY21.98% GW0
Given
(1-(1-Δ)365¼-tc

dt=c × (365¼-t) + Vt

ln(1-Δ)
1-(1-ε∇)t+365¼
1G Acc 7G Acc 7G Dec 1G Dec
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Spot Distance (dt) as (LYs)
Convert AUs to LYs:
dLY = dAU ×LY

63,241.1 AU
= 0.000 015 8 × dAU
Consider example:
d166=8,195.2AU×.0000158LY/AU=0.1296LY



166 dy74.67 AU/dy43.12% c8,195.2 AU0.1296 LY22.02% GW0
167 dy74.39 AU/dy42.96% c8,120.3 AU0.1284 LY22.05% GW0
168 dy4.11 AU/dy42.80% c8,045.8 AU0.1272 LY22.09% GW0
169 dy73.82 AU/dy42.64% c7,971.5 AU0.1261 LY22.13% GW0
170 dy73.54 AU/dy42.47% c7,897.5 AU0.1249 LY22.16% GW0
171 dy73.26 AU/dy42.31% c7,823.8 AU0.1237 LY22.20% GW0
172 dy72.98 AU/dy42.15% c7,750.4 AU0.1226 LY22.24% GW0
173 dy72.69 AU/dy41.98% c7,677.3 AU0.1214 LY22.27% GW0
174 dy72.41 AU/dy41.82% c7,604.4 AU0.1202 LY22.31% GW0
175 dy72.12 AU/dy41.65% c7,531.8 AU0.1191 LY22.35% GW0
176 dy71.84 AU/dy41.49% c7,459.5 AU0.1180 LY22.38% GW0
177 dy71.55 AU/dy41.32% c7,387.5 AU0.1168 LY22.42% GW0
178 dy71.26 AU/dy41.16% c7,315.8 AU0.1157 LY22.45% GW0
179 dy70.97 AU/dy40.99% c7,244.4 AU0.1146 LY22.49% GW0
180 dy70.68 AU/dy40.82% c7,173.3 AU0.1134 LY22.53% GW0
time
(t)
Spot Velocity
(Vt)
Countdown Distance
(dt)
Total Fuel
(ft)
1G Acc 7G Acc 7G Dec 1G Dec
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FUEL FACTORS OVERVIEW
Let EXHAUST PARTICLE SPEED = .99c.

Thus, RELATIVISTIC GROWTH impacts fuel flow.

Increase ∇ by EFFICIENCY FACTOR:  ε = 1.362,
to compensate for inevitable inefficiencies.

Daily Fuel CONSUMPTION RATE:
 ε∇ =0.000485 = .0485% GW/day.

DAILY GROSS WEIGHT REMAINDER:
1-ε∇ = 0.99951 = 99.951% GW.
181 dy70.39 AU/dy40.65% c7,102.4 AU0.1123 LY22.56% GW0
182 dy70.10 AU/dy40.49% c7,031.9 AU0.1112 LY22.60% GW0
183 dy69.81 AU/dy40.32% c6,961.6 AU0.1101 LY22.64% GW0
184 dy69.51 AU/dy40.15% c6,891.7 AU0.1090 LY22.67% GW0
185 dy69.22 AU/dy39.98% c6,822.0 AU0.1079 LY22.71% GW0
186 dy68.93 AU/dy39.81% c6,752.6 AU0.1068 LY22.74% GW0
187 dy68.63 AU/dy39.64% c6,683.5 AU0.1057 LY22.78% GW0
188 dy68.33 AU/dy39.47% c6,614.7 AU0.1046 LY22.82% GW0
189 dy68.04 AU/dy39.29% c6,546.2 AU0.1035 LY22.85% GW0
190 dy67.74 AU/dy39.12% c6,478.1 AU0.1024 LY22.89% GW0
191 dy67.44 AU/dy38.95% c6,410.2 AU0.1014 LY22.92% GW0
192 dy67.14 AU/dy38.78% c6,342.6 AU0.1003 LY22.96% GW0
193 dy66.84 AU/dy38.60% c6,275.3 AU0.0992 LY23.00% GW0
194 dy66.54 AU/dy38.43% c6,208.3 AU0.0982 LY23.03% GW0
195 dy66.24 AU/dy38¼% c6,141.6 AU0.0971 LY23.07% GW0
Given
(1-(1-Δ)365¼-tc

dt=c × (365¼-t) + Vt

ln(1-Δ)
1-(1-ε∇)t+365¼
1G Acc 7G Acc 7G Dec 1G Dec
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CONSIDER
CLASSICAL MOMENTUM
Conserve momentum.
Mship × Vship=mfuel × vExh
Divide each side
by one second.
Mship ×Vship

1 sec
=mfuel

1 sec
× vExh
Introduce g, "fuel flow per sec (ffsec)" and decimal light speed (dc × c).
Mship=ffsec

g
× dc × c
Solve for ffsec.
ffsec=g

dc × c
× MShip
Insert values:
g = 9.8065 m/s/s
dc×c=.99c=
296,794,533m/s
ffsec=0.00000330%MShip
Convert to ffday.
Recall 1 day = 86,400 sec
Thus, ffday = 86,400 ffsec
ffday=0.2854%MShip

196 dy65.93 AU/dy38.08% c6,075.2 AU0.0961 LY23.10% GW0
197 dy65.63 AU/dy37.90% c6,009.1 AU0.0950 LY23.14% GW0
198 dy65.32 AU/dy37.73% c5,943.3 AU0.0940 LY23.18% GW0
199 dy65.02 AU/dy37.55% c5,877.9 AU0.0929 LY23.21% GW0
200 dy64.71 AU/dy37.37% c5,812.7 AU0.0919 LY23.25% GW0
201 dy64.40 AU/dy37.20% c5,747.8 AU0.0909 LY23.28% GW0
202 dy64.10 AU/dy37.02% c5,683.3 AU0.0899 LY23.32% GW0
203 dy63.79 AU/dy36.84% c5,619.0 AU0.0889 LY23.36% GW0
204 dy63.48 AU/dy36.66% c5,555.1 AU0.0878 LY23.39% GW0
205 dy63.16 AU/dy36.48% c5,491.5 AU0.0868 LY23.43% GW0
206 dy62.85 AU/dy36.30% c5,428.1 AU0.0858 LY23.46% GW0
207 dy62.54 AU/dy36.12% c5,365.1 AU0.0848 LY23.50% GW0
208 dy62.23 AU/dy35.94% c5,302.5 AU0.0838 LY23.54% GW0
209 dy61.91 AU/dy35.76% c5,240.1 AU0.0829 LY23.57% GW0
210 dy61.60 AU/dy35.58% c5,178.0 AU0.0819 LY23.61% GW0
time
(t)
Spot Velocity
(Vt)
Countdown Distance
(dt)
Total Fuel
(ft)
1G Acc 7G Acc 7G Dec 1G Dec
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RELATIVISTIC MASS GROWTH
 
Lorentz Transform quantifies the relativistic growth due to particle speed. 

ffExh=ffsec

(1 - dc²)
=ffsec

(1 - (.99)²)
=ffsec

(1 - 0.9801)
Decimal "c" (dc) is particle speed as decimal light speed, c.
ffExh=ffsec

(0.0199)
=ffsec

0.141
=7  ffsec

TE BRAINSTORM: Let fuel flow per second (ffsec) be the original mass at rest.  Let exhaust fuel flow (ffExh) be the relativistic particle mass at an accelerated, very high velocity, perhaps 99% c for 7x growth.
ffExh = 7 × ffsec
211 dy61.28 AU/dy35.39% c5,116.3 AU0.0809 LY23.64% GW0
212 dy60.96 AU/dy35.21% c5,054.9 AU0.0799 LY23.68% GW0
213 dy60.64 AU/dy35.03% c4,993.7 AU0.0790 LY23.71% GW0
214 dy60.33 AU/dy34.84% c4,933.0 AU0.0780 LY23.75% GW0
215 dy60.01 AU/dy34.66% c4,872.5 AU0.0770 LY23.79% GW0
216 dy59.68 AU/dy34.47% c4,812.3 AU0.0761 LY23.82% GW0
217 dy59.36 AU/dy34.29% c4,752.5 AU0.0752 LY23.86% GW0
218 dy59.04 AU/dy34.10% c4,693.0 AU0.0742 LY23.89% GW0
219 dy58.72 AU/dy33.91% c4,633.8 AU0.0733 LY23.93% GW0
220 dy58.39 AU/dy33.72% c4,575.0 AU0.0723 LY23.96% GW0
221 dy58.07 AU/dy33.54% c4,516.4 AU0.0714 LY24.00% GW0
222 dy57.74 AU/dy33.35% c4,458.2 AU0.0705 LY24.03% GW0
223 dy57.41 AU/dy33.16% c4,400.3 AU0.0696 LY24.07% GW0
224 dy57.08 AU/dy32.97% c4,342.8 AU0.0687 LY24.11% GW0
225 dy56.76 AU/dy32.78% c4,285.5 AU0.0678 LY24.14% GW0
Given
(1-(1-Δ)365¼-tc

dt=c × (365¼-t) + Vt

ln(1-Δ)
1-(1-ε∇)t+365¼
1G Acc 7G Acc 7G Dec 1G Dec
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EFFICIENCY



Vessel must consume more fuel than needed for just theoretical G-force propulsion. More fuel is needed to overcome design flaws and power peripheral systems such as life support, navigation, communications and even entertainment.

We know propulsion efficiency improves as engineers design ever better  systems. Thus, Thought Experiment (TE) arbitrarily assumes a dynamic efficiency model starting much less than 100% but trending toward 100% over time.  



226 dy56.43 AU/dy32.59% c4,228.7 AU0.0669 LY24.18% GW0
227 dy56.09 AU/dy32.40% c4,172.1 AU0.0660 LY24.21% GW0
228 dy55.76 AU/dy32.21% c4,115.9 AU0.0651 LY24.25% GW0
229 dy55.43 AU/dy32.01% c4,060.0 AU0.0642 LY24.28% GW0
230 dy55.10 AU/dy31.82% c4,004.4 AU0.0633 LY24.32% GW0
231 dy54.76 AU/dy31.63% c3,949.2 AU0.0624 LY24.35% GW0
232 dy54.43 AU/dy31.43% c3,894.3 AU0.0616 LY24.39% GW0
233 dy54.09 AU/dy31.24% c3,839.7 AU0.0607 LY24.43% GW0
234 dy53.75 AU/dy31.04% c3,785.5 AU0.0599 LY24.46% GW0
235 dy53.41 AU/dy30.85% c3,731.6 AU0.0590 LY24.50% GW0
236 dy53.07 AU/dy30.65% c3,678.0 AU0.0582 LY24.53% GW0
237 dy52.73 AU/dy30.46% c3,624.8 AU0.0573 LY24.57% GW0
238 dy52.39 AU/dy30.26% c3,572.0 AU0.0565 LY24.60% GW0
239 dy52.05 AU/dy30.06% c3,519.4 AU0.0557 LY24.64% GW0
240 dy51.70 AU/dy29.86% c3,467.3 AU0.0548 LY24.67% GW0
time
(t)
Spot Velocity
(Vt)
Countdown Distance
(dt)
Total Fuel
(ft)
1G Acc 7G Acc 7G Dec 1G Dec
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ADJUST DAILY FUEL FLOW (ffDay)
for relativistic growth and inevitable inefficiency.
BEST GUESS BRAINSTORM for daily fuel consumption first involves downsizing fuel estimate due to relativistic mass growth.  Recall: fuel particles at .99c velocity should grow 7x!!  Formula uses ∇ to designate daily relativistic fuel.

A good thing too, cuz propulsion efficiency will likely start out very low; thus, we upsize estimate for fuel consumed to make up for vessel's inefficiency. Following formula uses efficiency factor,  ε, to increase estimate of daily fuel.

After all this brainstorming, TE proposes a daily decrement of ε∇ = 0.047% of vessel's initial Gross Weight (GW0) .  Compute each day's cumulative fuel consumption as % of GW0 Recall total G-force time includes 1 year of acceleration plus deceleration days.
ft = 1 - (1-ε∇)= 1 -(1-.00047)t+365¼ GW0
EXAMPLE: 241 days      Let GW0 = 100 tons.
f241 = 1 - (0.99953)241+365¼ = 1 - (0.7520) GW0
f241= (100-75.20)% GW0  24.71% GW0= 24.71 tons
241 dy51.36 AU/dy29.66% c3,415.4 AU0.0540 LY 24.71% GW0
242 dy51.02 AU/dy29.46% c3,363.9 AU0.0532 LY 24.74% GW0
243 dy50.67 AU/dy29.26% c3,312.8 AU0.0524 LY 24.78% GW0
244 dy50.32 AU/dy29.06% c3,262.0 AU0.0516 LY24.81% GW0
245 dy49.97 AU/dy28.86% c3,211.5 AU0.0508 LY 24.85% GW0
246 dy49.62 AU/dy28.66% c3,161.4 AU0.0500 LY 24.88% GW0
247 dy49.27 AU/dy28.46% c3,111.7 AU0.0492 LY24.92% GW0
248 dy48.92 AU/dy28.26% c3,062.3 AU0.0484 LY 24.95% GW0
249 dy48.57 AU/dy28.05% c3,013.2 AU0.0476 LY 24.99% GW0
250 dy48.22 AU/dy27.85% c2,964.5 AU0.0469 LY25.02% GW0
251 dy47.86 AU/dy27.64% c2,916.2 AU0.0461 LY 25.06% GW0
252 dy47.51 AU/dy27.44% c2,868.2 AU0.0454 LY 25.09% GW0
253 dy47.15 AU/dy27.23% c2,820.5 AU0.0446 LY 25.09% GW0
254 dy46.79 AU/dy27.03% c2,773.3 AU0.0439 LY 25.13% GW0
255 dy46.44 AU/dy26.82% c2,726.3 AU0.0431 LY 25.20% GW0
Given
(1-(1-Δ)365¼-tc

dt=c × (365¼-t) + Vt

ln(1-Δ)
1-(1-ε∇)t+365¼
1G Acc 7G Acc 7G Dec 1G Dec
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HOW FAST, SO FAR???
After 256 days 
of G-force propulsion, 
Thot Exp (TE) brainstorms that 
interstellar vessel velocity is at 26.61% c
 as measured by our friends way back on Earth.



256 dy46.08 AU/dy26.61% c2,679.8 AU0.0424 LY25.23% GW0
257 dy45.72 AU/dy26.40% c2,633.6 AU0.0416 LY25.27% GW0
258 dy45.35 AU/dy26.19% c2,587.7 AU0.0409 LY25.30% GW0
259 dy44.99 AU/dy25.98% c2,542.3 AU0.0402 LY25.34% GW0
260 dy44.63 AU/dy25.77% c2,497.2 AU0.0395 LY25.37% GW0
261 dy44.26 AU/dy25.56% c2,452.4 AU0.0388 LY25.41% GW0
262 dy43.90 AU/dy25.35% c2,408.0 AU0.0381 LY25.44% GW0
263 dy43.53 AU/dy25.14% c2,364.0 AU0.0374 LY25.48% GW0
264 dy43.16 AU/dy24.93% c2,320.3 AU0.0367 LY25.51% GW0
265 dy42.80 AU/dy24.72% c2,277.1 AU0.0360 LY25.55% GW0
266 dy42.43 AU/dy24.50% c2,234.1 AU0.0353 LY25.58% GW0
267 dy42.05 AU/dy24.29% c2,191.6 AU0.0347 LY25.62% GW0
268 dy41.68 AU/dy24.07% c2,149.4 AU0.0340 LY25.65% GW0
269 dy41.31 AU/dy23.86% c2,107.6 AU0.0333 LY25.69% GW0
270 dy40.94 AU/dy23.64% c2,066.2 AU0.0327 LY25.72% GW0
time
(t)
Spot Velocity
(Vt)
Countdown Distance
(dt)
Total Fuel
(ft)
1G Acc 7G Acc 7G Dec 1G Dec
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HOW FAR, SO FAR???
After 271 days 
of G-force deceleration, 
Thot Exp (TE) brainstorms that 
distance to destination is at 0.0320 LY
 which equals 2,025.1 AU
counting down 
ever closer.



271 dy40.56 AU/dy23.43% c2,025.1 AU0.0320 LY25.76% GW0
272 dy40.19 AU/dy23.21% c1,984.5 AU0.0314 LY25.79% GW0
273 dy39.81 AU/dy22.99% c1,944.2 AU0.0307 LY25.83% GW0
274 dy9.43 AU/dy22.77% c1,904.2 AU0.0301 LY25.86% GW0
275 dy39.05 AU/dy22.55% c1,864.7 AU0.0295 LY25.90% GW0
276 dy38.67 AU/dy22.33% c1,825.5 AU0.0289 LY25.93% GW0
277 dy38.29 AU/dy22.11% c1,786.7 AU0.0283 LY25.97% GW0
278 dy37.91 AU/dy21.89% c1,748.3 AU0.0276 LY26.00% GW0
279 dy37.52 AU/dy21.67% c1,710.3 AU0.0270 LY26.04% GW0
280 dy37.14 AU/dy21.45% c1,672.7 AU0.0264 LY26.07% GW0
281 dy36.75 AU/dy21.23% c1,635.4 AU0.0259 LY26.10% GW0
282 dy36.37 AU/dy21.00% c1,598.6 AU0.0253 LY26.14% GW0
283 dy35.98 AU/dy20.78% c1,562.1 AU0.0247 LY26.17% GW0
284 dy35.59 AU/dy20.55% c1,526.0 AU0.0241 LY26.21% GW0
285 dy35.20 AU/dy20.33% c1,490.3 AU0.0236 LY26.24% GW0
Given
(1-(1-Δ)365¼-tc

dt=c×(365¼-t) + Vt

ln(1-Δ)
1-(1-ε∇)t+365¼
1G Acc 7G Acc 7G Dec 1G Dec
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HOW MUCH FUEL, SO FAR???
After 286 days 
of G-force deceleration, 
Thot Exp (TE) brainstorms that 
vessel gross weight decreases to 73.71% GW0
THEREFORE, remaining (26.28% GW0
was total fuel consumed (ft) 
to propel our vessel.



286 dy34.81 AU/dy20.10% c1,455.0 AU0.0230 LY26.28% GW0
287 dy34.42 AU/dy19.88% c1,420.1 AU0.0225 LY26.31% GW0
288 dy34.02 AU/dy19.65% c1,385.5 AU0.0219 LY26.35% GW0
289 dy33.63 AU/dy19.42% c1,351.4 AU0.0214 LY26.38% GW0
290 dy33.23 AU/dy19.19% c1,317.7 AU0.0208 LY26.41% GW0
291 dy32.84 AU/dy18.96% c1,284.3 AU0.0203 LY26.45% GW0
292 dy32.44 AU/dy18.73% c1,251.4 AU0.0198 LY26.48% GW0
293 dy32.04 AU/dy18.50% c1,218.9 AU0.0193 LY26.52% GW0
294 dy31.64 AU/dy18.27% c1,186.7 AU0.0188 LY26.55% GW0
295 dy31.24 AU/dy18.04% c1,155.0 AU0.0183 LY26.59% GW0
296 dy30.83 AU/dy17.81% c1,123.6 AU0.0178 LY26.62% GW0
297 dy30.43 AU/dy17.58% c1,092.7 AU0.0173 LY26.66% GW0
298 dy30.03 AU/dy17.34% c1,062.2 AU0.0168 LY26.69% GW0
299 dy29.62 AU/dy17.11% c1,032.0 AU0.0163 LY26.72% GW0
300 dy29.21 AU/dy16.87% c1,002.3 AU0.0158 LY26.76% GW0
time
(t)
Spot Velocity
(Vt)
Countdown Distance
(dt)
Total Fuel
(ft)
1G Acc 7G Acc 7G Dec 1G Dec
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INITIAL GROSS WEIGHT (GW0)
Empty vessel has no pax, no cargo and no fuel (aka "dry"). Thus, empty vessel's GW is mass of vessel's structure and equipment. HOWEVER, vessel's function is transporting pax and cargo.  FURTHERMORE, much like today's airliners in the sky, G-force vessel requires considerable initial fuel which could = ½ GW0.


EXAMPLE: If vessel's total mass = 100 tons, fuel could = 50 tons!!!



INITIAL GROSS WEIGHT (GW0) is vessel's total mass at very beginning of Phase I. Acceleration.  This includes considerable fuel which decreases throughout powered flight.
301 dy28.80 AU/dy16.64% c973.0 AU0.0154 LY26.79% GW0
302 dy28.40 AU/dy16.40% c944.1 AU0.0149 LY26.83% GW0
303 dy27.98 AU/dy16.16% c915.6 AU0.0145 LY26.86% GW0
304 dy27.57 AU/dy15.92% c887.5 AU0.0140 LY26.90% GW0
305 dy27.16 AU/dy15.69% c859.8 AU0.0136 LY26.93% GW0
306 dy26.75 AU/dy15.45% c832.6 AU0.0132 LY26.96% GW0
307 dy26.33 AU/dy15.21% c805.7 AU0.0127 LY27.00% GW0
308 dy25.91 AU/dy14.97% c779.3 AU0.0123 LY27.03% GW0
309 dy25.50 AU/dy14.73% c753.3 AU0.0119 LY27.07% GW0
310 dy25.08 AU/dy14.48% c727.7 AU0.0115 LY27.10% GW0
311 dy24.66 AU/dy14.24% c702.5 AU0.0111 LY27.13% GW0
312 dy24.24 AU/dy14.00% c677.8 AU0.0107 LY27.17% GW0
313 dy23.82 AU/dy13.75% c653.4 AU0.0103 LY27.20% GW0
314 dy23.39 AU/dy13.51% c629.5 AU0.0100 LY27.24% GW0
315 dy22.97 AU/dy13.26% c606.1 AU0.0096 LY27.27% GW0
Given
(1-(1-Δ)365¼-tc

dt=c × (365¼-t) + Vt

ln(1-Δ)
1-(1-ε∇)t+365¼
1G Acc 7G Acc 7G Dec 1G Dec
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DAILY GROSS WEIGHT (GWt)
 FUEL CONSUMPTION: ε∇ =  .0485% GW/day.
For each day of G-force, compute daily gross weight via:
EXPONENTIAL EQUATION: GWt =  (1-ε∇)t =(.99515)t 
INITIAL GROSS WEIGHT:  GW=  (1-ε∇)0 = 1.000 GW0



G-force propulsion consumes fuel (both acceleration and deceleration), and ship's gross weight continually decreases.  THUS, after 1 year of acceleration
GW1-year =  (1-ε∇)365¼ = 84.28% GW0



Table counts days of deceleration (t) from 0 to 365¼.
GWt =  (1-ε∇)t+365¼ GW0
EXAMPLE:  GW316 =  (.99515)316+365¼ GW=  72.69% GW0
316 dy22.54 AU/dy13.02% c583.0 AU0.0092 LY27.31% GW0
317 dy22.11 AU/dy12.77% c560.4 AU0.0089 LY27.34% GW0
318 dy21.69 AU/dy12.52% c538.2 AU0.0085 LY27.37% GW0
319 dy21.26 AU/dy12.28% c516.4 AU0.0082 LY27.41% GW0
320 dy20.83 AU/dy12.03% c495.0 AU0.0078 LY27.44% GW0
321 dy20.39 AU/dy11.78% c474.1 AU0.0075 LY27.48% GW0
322 dy19.96 AU/dy11.53% c453.6 AU0.0072 LY27.51% GW0
323 dy19.53 AU/dy11.28% c433.6 AU0.0069 LY27.54% GW0
324 dy19.09 AU/dy11.03% c414.0 AU0.0065 LY27.58% GW0
325 dy18.65 AU/dy10.77% c394.8 AU0.0062 LY27.61% GW0
326 dy18.22 AU/dy10.52% c376.1 AU0.0059 LY27.64% GW0
327 dy17.78 AU/dy10.27% c357.8 AU0.0057 LY27.68% GW0
328 dy17.34 AU/dy10.01% c339.9 AU0.0054 LY27.71% GW0
329 dy16.89 AU/dy9.76% c322.5 AU0.0051 LY27.75% GW0
330 dy16.45 AU/dy9.50% c305.5 AU0.0048 LY27.78% GW0
time
(t)
Spot Velocity
(Vt)
Countdown Distance
(dt)
Total Fuel
(ft)
1G Acc 7G Acc 7G Dec 1G Dec
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TE BRAINSTORMS CLASSICAL FUEL
ASSUME EXHAUST PARTICLE VEL = .99c

Routinely achieved by today's synchrotrons.

MShip ×VShip=mfuel×vfuel
Rearrange and substitute:
ffday=MShip

.99c
×g×86,400 sec

day
Values for light speed, c, & Earth gravity, g.
ffday=MShip

296,794,533m/s
×9.8065 m/s

sec
×86,400 sec

day
Classical daily fuel consumption computed:ffday  = 0.2854% ship's mass (MShip)HOWEVER, needs adjusting forrelativistic mass growth &inevitable inefficiency.

331 dy16.01 AU/dy9.24% c289.0 AU0.0046 LY27.81% GW0
332 dy15.56 AU/dy8.99% c272.9 AU0.0043 LY27.85% GW0
333 dy15.11 AU/dy8.73% c257.2 AU0.0041 LY27.88% GW0
334 dy14.66 AU/dy8.47% c242.0 AU0.0038 LY27.92% GW0
335 dy14.22 AU/dy8.21% c227.3 AU0.0036 LY27.95% GW0
336 dy13.76 AU/dy7.95% c213.0 AU0.0034 LY27.98% GW0
337 dy13.31 AU/dy7.69% c199.2 AU0.0031 LY28.02% GW0
338 dy12.86 AU/dy7.43% c185.8 AU0.0029 LY28.05% GW0
339 dy12.40 AU/dy7.16% c172.8 AU0.0027 LY28.08% GW0
340 dy11.95 AU/dy6.90% c160.4 AU0.0025 LY28.12% GW0
341 dy11.49 AU/dy6.64% c148.3 AU0.0023 LY28.15% GW0
342 dy11.03 AU/dy6.37% c136.8 AU0.0022 LY28.18% GW0
343 dy10.57 AU/dy6.11% c125.7 AU0.0020 LY28.22% GW0
344 dy10.11 AU/dy5.84% c115.0 AU0.0018 LY28.25% GW0
345 dy9.65 AU/dy5.57% c104.8 AU0.0017 LY28.29% GW0
Given
(1-(1-Δ)365¼-tc

dt=c × (365¼-t) + Vt

ln(1-Δ)
1-(1-ε∇)t+365¼
1G Acc 7G Acc 7G Dec 1G Dec
TOP Prev⇑ Next⇓ BOT
TE BRAINSTORMS PRACTICAL FUEL
ASSUME EXHAUST PARTICLE VEL = .99c
CONSIDER RELATIVISTIC GROWTH
which decreases daily fuel requirement.
Divide ffday by Lorentz Transform.
=0.2854% MShip

1 / √(1 - 0.99²)

=
0.2854% MShip

7
CONSIDER INEVITABLE INEFFICIENCY
which increases daily requirement.
TE brainstorms an arbitrary Efficiency Factor, ε.
ε∇=0.2854% MShip

7
×ε=.0485% GW

day
Adjust for relativity & inefficiency: ADJUSTED DAILY FUEL: ffAdj  = ε∇ =  .0485% GW/dayNOTE: Due to constant fuel consumption, ship's  mass shrinks constantly.but above percentage persists on and on for every G-force day.Let initial Gross Weight (GW0)= 100 tonnes.
EXAMPLE: From 99 to 101 days of G-force deceleration, note  slight decreases in daily fuel consumption due to decreasing GW.
'F' is cumulative fuel consumed; 'f' is incremental fuel.
346 dy9.19 AU/dy5.31% c95.1 AU0.0015 LY28.32% GW0
347 dy8.72 AU/dy5.04% c85.8 AU0.0014 LY28.35% GW0
348 dy8.26 AU/dy4.77% c77.0 AU0.0012 LY28.39% GW0
349 dy7.79 AU/dy4.50% c68.7 AU0.0011 LY28.42% GW0
350 dy7.32 AU/dy4.23% c60.9 AU0.0010 LY28.45% GW0
351 dy6.85 AU/dy3.96% c53.5 AU0.0008 LY28.49% GW0
352 dy6.38 AU/dy3.68% c46.6 AU0.0007 LY28.52% GW0
353 dy5.90 AU/dy3.41% c40.1 AU0.0006 LY28.55% GW0
354 dy5.43 AU/dy3.14% c34.1 AU0.0005 LY28.59% GW0
355 dy4.95 AU/dy2.86% c28.6 AU0.0005 LY28.62% GW0
356 dy4.48 AU/dy2.59% c23.6 AU0.0004 LY28.65% GW0
357 dy4.00 AU/dy2.31% c19.1 AU0.0003 LY28.69% GW0
358 dy3.52 AU/dy2.03% c15.0 AU0.0002 LY28.72% GW0
359 dy3.04 AU/dy1.75% c11.4 AU0.0002 LY28.75% GW0
360 dy2.56 AU/dy1.48% c8.3 AU0.0001 LY28.79% GW0
time
(t)
Spot Velocity
(Vt)
Countdown Distance
(dt)
Total Fuel
(ft)
1G Acc 7G Acc 7G Dec 1G Dec
TC Prev⇑
CONSUMPTION CONCLUSION
Compare one year's fuel consumption (due to G-force acceleration) with two years' fuel consumption (both acceleration & deceleration).
Intuition initially compels one to conclude that two years of G-force takes twice as much fuel as one year.  However, constant consumption requires exponentiation to more accurately determine correct values.
SURPRISE!!!   THOT EXP confesses to a small prank on the readers!  TE used an efficiency factor, ε, for Deceleration Fuel values of 1.000 (very unlikely cuz 1.0 indicates perfect efficiency). This means Table's fuel consumption values are minimums.  Actual values will likely start higher!!!
360 dy2.56 AU/dy1.48% c8.3 AU0.0001 LY 28.79% GW0
361 dy2.07 AU/dy1.20% c5.7 AU0.0001 LY28.82% GW0
362 dy1.59 AU/dy0.92% c3.6 AU0.0001 LY28.85% GW0
363 dy1.10 AU/dy0.64% c1.9 AU0.0000 LY 28.89% GW0
364 dy0.61 AU/dy0.35% c0.8 AU0.0000 LY28.92% GW0
365 dy0.12 AU/dy0.07% c0.1 AU0.0000 LY28.95% GW0
365¼ d0.00 AU/dy0.00% c0.0 AU0.0000 LY29.00% GW0
Given
(1-(1-Δ)365¼-tc

dt=c × (365¼-t) + Vt

ln(1-Δ)
1-(1-ε∇)t+365¼
SUMMARY
PHASE I. G-force Acceleration 
consumes fuel in an exponentially decreasing way.
SIMPLE SUM: 4.57 tons + 8.94 tons = 13.51 tons 
HOWEVER: 13.51 tons > 13.10 tons; fuel actually consumed.
PHASE II.  Cruise 
at Constant Velocity (.6457 c). 
Pause G-force propulsion for a few years to save fuel; HOWEVER, life support, navigation, communication, etc. still need power; perhaps, supplied by onboard fusion reactor.
PHASE III. G-force Deceleration 
Vessel velocity must decrease back to near zero velocity precisely at destination. Thus, decelerate for exactly same distance & duration as Phase I.  Crew must carefully navigate to precise location to reinitiate G-force propulsion.







VOLUME 0: ELEVATIONAL
VOLUME I: ASTEROIDAL
VOLUME II: INTERPLANETARY
VOLUME III: INTERSTELLAR










SLIDESHOW







1G Acceleration for 1 year.
7G Acceleration for 100 days.
7G Deceleration for 48¼ days.
1G Deceleration for 1 year.







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